Called object is not a function or function pointer ошибка

I am trying to write a program which implements the Pop and Push functions. The problem is, I am trying to pass the pointer that points to integer Top to the function, so that this integer keeps changing, but when I try to compile I always get this line:

**error: called object is not a function or function pointer (*t)—

#include<stdio.h>
#include<stdlib.h>

#define MAX 10
int push(int stac[], int *v, int *t)
{
  if((*t) == MAX-1)
  {
      return(0);
  }
  else
  {
      (*t)++;
      stac[*t] = *v;
      return *v;
   }
}

int pop(int stac[], int *t)
{
 int popped;
 if((*t) == -1)
 {
      return(0);
 }
 else
 {
     popped = stac[*t]
     (*t)--;
     return popped;
 } 
}
int main()
{
int stack[MAX];
int value;
int choice;
int decision;
int top;
top = -1;
do{
   printf("Enter 1 to push the valuen");
   printf("Enter 2 to pop the valuen");
   printf("Enter 3 to exitn");
   scanf("%d", &choice);
   if(choice == 1)
   {
       printf("Enter the value to be pushedn");
       scanf("%d", &value);
       decision = push(stack, &value, &top);
       if(decision == 0)
       { 
           printf("Sorry, but the stack is fulln");  
       }
       else
       {
           printf("The value which is pushed is: %dn", decision);
       }
   }
   else if(choice == 2)
    {
         decision = pop(stack, &top);
        if(decision == 0)
          {
               printf("The stack is emptyn");
          }
         else
          {
              printf("The value which is popped is: %dn", decision);
          }

    }
 }while(choice != 3);
 printf("Top is %dn", top);

}

I try to insert many values into a queue and delete the first value in the queue.
However, I have an error when I want to print the queue after deleting values.

There is my code:

char queue[100];
int i=-1;

int *delete_queue(int value){

    int j;
    for(j= 0; j< 10; j++){
    queue[j]= queue[j+1];   
    }

    return queue;

}

void insert_queue(int value){

    i= i + 1;
    queue[i] = value;

}

void print_queue(int *p){

    int v;
    for(v =0; v < 5; v++){
        printf(">> %d n", *p(v+1) );
    }

}

int main(int argc, char const *argv[])
{
    //int v ;
    int *new_queue;
    insert_queue(33);
    insert_queue(22);
    insert_queue(11);

    new_queue= delete_queue(33);
    print_queue(new_queue);
    // for(v =0; v < 5; v++){
    //  printf(">> %d n", *new_queue(v+1) );
    // }

return 0;
}

The error is:

delete_queue_test.c: In function ‘print_queue’:
delete_queue_test.c:33:23: error: called object ‘p’ is not a function or  
function pointer
printf(">> %d n", *p(v+1) );
                   ^

please help me fix it, thank you.

  z=x-~y-1;
    printf("%d",z);
  z=(x^y)+2(x&y);
    printf("%d",z);
  z=(x|y)+(x&y);
    printf("%d",z);
  z=2(x|y)-(x^y);
    printf("%d",z);

10:11: error: called object is not a function or function pointer 
z=(x^y)+2(x&y); 
        ^ 

2 ответа

Лучший ответ

z=(x^y)+2(x&y);

z=(x^y)+2*(x&y);

z=2(x|y)-(x^y);

z=2*(x|y)-(x^y);