Argument of type int is not iterable ошибка

I am getting this error when I run my program and I have no idea why. The error is occurring on the line that says «if 1 not in c:»

Code:

matrix = [
    [0, 0, 0, 5, 0, 0, 0, 0, 6],
    [8, 0, 0, 0, 4, 7, 5, 0, 3],
    [0, 5, 0, 0, 0, 3, 0, 0, 0],
    [0, 7, 0, 8, 0, 0, 0, 0, 9],
    [0, 0, 0, 0, 1, 0, 0, 0, 0],
    [9, 0, 0, 0, 0, 4, 0, 2, 0],
    [0, 0, 0, 9, 0, 0, 0, 1, 0],
    [7, 0, 8, 3, 2, 0, 0, 0, 5],
    [3, 0, 0, 0, 0, 8, 0, 0, 0],
    ]
a = 1
while a:
     try:
        for c, row in enumerate(matrix):
            if 0 in row:
                print("Found 0 on row,", c, "index", row.index(0))
                if 1 not in c:
                    print ("t")
    except ValueError:
         break

What I would like to know is how I can fix this error from happening an still have the program run correctly.

Thanks in advance!

In Python, the error TypeError: argument of type ‘int’ is not iterable occurs when the membership operator (in, not in) is used to validate the membership of a value in non iteratable objects such as list, tuple, dictionary. The membership operator can be used to verify memberships in variables such as strings, numbers, tuples and dictionary.

The membership operator (in, not in) in Python is used to test whether or not the given value exists in another variable. The operator searches the value in an iterable object. The error “TypeError: argument of type ‘int’ is not iterable” is due to the search of value in a non-iterable object.

Through this article, we can see what this error is, how this error can be solved. This type error is due to missing of an non-iterable object in the membership operator. The error would be thrown as like below.

Traceback (most recent call last):
  File "/Users/python/Desktop/test.py", line 3, in <module>
    print x in y
TypeError: argument of type 'int' is not iterable
[Finished in 0.1s with exit code 1]

Different Variation of the error

In different contexts the “TypeError: argument of type ‘int’ is not iterable” error is thrown in various forms in python. The numerous variations of TypeError are given below.

TypeError: argument of type 'int' is not iterable
TypeError: argument of type 'float' is not iterable
TypeError: argument of type 'bool' is not iterable
TypeError: argument of type 'complex' is not iterable
TypeError: argument of type 'long' is not iterable
TypeError: argument of type 'NoneType' is not iterable
TypeError: argument of type 'type' is not iterable

Root Cause

The membership operator searches for a value in an iterable object such as list, tuple, dictionary. If the value presents in an iterable object, returns true, otherwise it returns false. If you are looking for a value in non-iterable object such as int, float, boolean, python can not identify the presents of the value. In this case the python interpreter will throw that error.

How to reproduce this issue

If you are looking for a value in non-iterable object such as int, float, boolean, the python interpreter will throw this error. The code below searches an integer value in another integer value. This error will be thrown, as an integer value is not an iterable entity.

x = 4
y = 4
print x in y

Output

Traceback (most recent call last):
  File "/Users/python/Desktop/test.py", line 3, in <module>
    print x in y
TypeError: argument of type 'int' is not iterable

Solution 1

If the membership operator (in, not in) is used, the value present in an iterable object such as list, tuple, or dictionary should be checked. Verify that the program looks for iterable objects. In the membership operator, the wrong variable is used, or the wrong value is given in the variable.

x = 4
y = [4, 5]
print x in y

Output

True

Solution 2

If you want to check a value with another value, you should not use the Membership Operator. Instead, the logical operator is used to compare two values. The logical operator in python will compare two values. The code below shows how to use comparison of the value.

x = 4
y = 4
print x == y

Output

True

Solution 3

If the membership operator variable contains None value, the membership operator would not be able to iterate that value. Membership operator throws “TypeError: the ‘NoneType’ argument is not iterable” error. Either Null check must be performed or assigned with an iterable object as the default.

x = 4
y = None
print x in y

Output

Traceback (most recent call last):
  File "/Users/python/Desktop/test.py", line 3, in <module>
    print x in y
TypeError: argument of type 'NoneType' is not iterable

Solution

x = 4
y = []
print x in y

Output

False

Solution 4

If the type of the value is used in the membership operator, python interpreter will throw “TypeError: type ‘type’ argument is not iterable” error. The value presents check can not be performed on the type of the object. It is because of error in typing. The types such as list, tuple, dict are to be modified to functions such as list(), tuple(), dict().

x = 4
y = list
print x in y

Output

Traceback (most recent call last):
  File "/Users/python/Desktop/test.py", line 3, in <module>
    print x in y
TypeError: argument of type 'type' is not iterable

Solution

x = 4
y = list()
print x in y

Output

False

Integers and iterables are distinct objects in Python. An integer stores a whole number value, and an iterable is an object capable of returning elements one at a time, for example, a list. If you try to iterate over an integer value, you will raise the error “TypeError: ‘int’ object is not iterable”. You must use an iterable when defining a for loop, for example, range(). If you use a function that requires an iterable, for example, sum(), use an iterable object as the function argument, not integer values.

This tutorial will go through the error in detail. We will go through two example scenarios and learn how to solve the error.

TypeError: ‘int’ object is not iterable

TypeError occurs in Python when you try to perform an illegal operation for a specific data type. For example, if you try to index a floating-point number, you will raise the error: “TypeError: ‘float’ object is not subscriptable“. The part ‘int’ object is not iterable tells us the TypeError is specific to iteration. You cannot iterate over an object that is not iterable. In this case, an integer, or a floating-point number.

An iterable is a Python object that you can use as a sequence. You can go to the next item in the sequence using the next() method.

Let’s look at an example of an iterable by defining a dictionary:

d = {"two": 2, "four":4, "six": 6, "eight": 8, "ten": 10}

iterable = d.keys()

print(iterable)

dict_keys(['two', 'four', 'six', 'eight', 'ten'])

The output is the dictionary keys, which we can iterate over. You can loop over the items and get the values using a for loop:

for item in iterable:

    print(d[item])

Here you use item as the index for the key in the dictionary. The following result will print to the console:

2
4
6
8
10

You can also create an iterator to use the next() method

d = {"two": 2, "four":4, "six": 6, "eight": 8, "ten": 10} 

iterable = d.keys()

iterator = iter(iterable)

print(next(iterator))

print(next(iterator))

two

four

The code returns the first and second items in the dictionary. Let’s look at examples of trying to iterate over an integer, which raises the error: “TypeError: ‘int’ object is not iterable”.

Example #1: Incorrect Use of a For Loop

Let’s consider a for loop where we define a variable n and assign it the value of 10. We use n as the number of loops to perform: We print each iteration as an integer in each loop.

n = 10

for i in n:

    print(i)

TypeError                                 Traceback (most recent call last)
      1 for i in n:
      2     print(i)
      3 

TypeError: 'int' object is not iterable

You raise the error because for loops are used to go across sequences. Python interpreter expects to see an iterable object, and integers are not iterable, as they cannot return items in a sequence.

Solution

You can use the range() function to solve this problem, which takes three arguments.

range(start, stop, step)

Where start is the first number from which the loop will begin, stop is the number at which the loop will end and step is how big of a jump to take from one iteration to the next. By default, start has a value of 0, and step has a value of 1. The stop parameter is compulsory.

n = 10

for i in range(n):

   print(i)

0
1
2
3
4
5
6
7
8
9

The code runs successfully and prints each value in the range of 0 to 9 to the console.

Example #2: Invalid Sum Argument

The sum() function returns an integer value and takes at most two arguments. The first argument must be an iterable object, and the second argument is optional and is the first number to start adding. If you do not use a second argument, the sum function will add to 0. Let’s try to use the sum() function with two integers:

x = 2

y = 6

print(sum(x, y))

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
1 print(sum(x,y))

TypeError: 'int' object is not iterable

The code is unsuccessful because the first argument is an integer and is not iterable.

Solution

You can put our integers inside an iterable object to solve this error. Let’s put the two integers in a list, a tuple, a set and a dictionary and then use the sum() function.

x = 2

y = 6

tuple_sum = (x, y)

list_sum = [x, y]

set_sum = {x, y}

dict_sum = {x: 0, y: 1}

print(sum(tuple_sum))

print(sum(list_sum))

print(sum(set_sum))

print(sum(dict_sum))

8
8
8
8

The code successfully runs. The result remains the same whether we use a tuple, list, set or dictionary. By default, the sum() function sums the key values.

Summary

Congratulations on reading to the end of this tutorial. The error “TypeError: ‘int’ object is not iterable” occurs when you try to iterate over an integer. If you define a for loop, you can use the range() function with the integer value you want to use as the stop argument. If you use a function that requires an iterable, such as the sum() function, you must put your integers inside an iterable object like a list or a tuple.

For further reading on the ‘not iterable’ TypeError go to the articles:

• How to Solve Python TypeError: ‘NoneType’ object is not iterable.
• How to Solve Python TypeError: ‘method’ object is not iterable.

Go to the online courses page on Python to learn more about Python for data science and machine learning.

Have fun and happy researching!